Expanding (x + 1)³
The expression (x + 1)³ represents the cube of the binomial (x + 1). To expand this expression, we can use the following methods:
1. Repeated Multiplication
The simplest method is to multiply (x + 1) by itself three times:
- Step 1: (x + 1) * (x + 1) = x² + 2x + 1
- Step 2: (x² + 2x + 1) * (x + 1) = x³ + 3x² + 3x + 1
Therefore, (x + 1)³ = x³ + 3x² + 3x + 1
2. Binomial Theorem
The Binomial Theorem provides a general formula for expanding any power of a binomial:
(a + b)ⁿ = ∑(n choose k) * a^(n-k) * b^k
Where:
- n is the power to which the binomial is raised.
- k ranges from 0 to n.
- (n choose k) represents the binomial coefficient, which is calculated as n! / (k! * (n-k)!).
Applying this to (x + 1)³, we have:
- n = 3
- a = x
- b = 1
Substituting these values into the Binomial Theorem, we get:
(x + 1)³ = (3 choose 0) * x³ * 1⁰ + (3 choose 1) * x² * 1¹ + (3 choose 2) * x¹ * 1² + (3 choose 3) * x⁰ * 1³
Calculating the binomial coefficients:
- (3 choose 0) = 1
- (3 choose 1) = 3
- (3 choose 2) = 3
- (3 choose 3) = 1
Substituting these values back into the equation:
(x + 1)³ = 1 * x³ * 1 + 3 * x² * 1 + 3 * x * 1 + 1 * 1 * 1
Simplifying the equation, we obtain:
**(x + 1)³ = x³ + 3x² + 3x + 1
3. Pascal's Triangle
Pascal's Triangle provides a visual representation of binomial coefficients. The numbers in each row correspond to the coefficients of the expanded binomial.
To expand (x + 1)³, we need the coefficients from the fourth row of Pascal's Triangle (remembering the top row is row 0):
1 3 3 1
These coefficients correspond to the terms in the expanded form of (x + 1)³:
(x + 1)³ = 1 * x³ + 3 * x² + 3 * x + 1 * 1
Simplifying the equation, we get:
**(x + 1)³ = x³ + 3x² + 3x + 1
Conclusion
All three methods demonstrate that the expanded form of (x + 1)³ is x³ + 3x² + 3x + 1. The method you choose depends on your preference and the complexity of the binomial expression.